GM Service Manual Online
For 1990-2009 cars only

Wheel Bearings Diagnosis Utility and 4WD Pickup

Step

Action

Value(s)

Yes

No

DEFINITION: This vehicle uses an integral hub/bearing the front and rear wheels. Replace the hub/bearing if damage exists or if the hub/bearing exceeds the maximum lateral runout specification.

1

  1. Raise and suitably support the vehicle. Refer to Lifting and Jacking the Vehicle in General Information.
  2. Remove the tire and the wheel. Refer to Tire and Wheel Removal and Installation in Tire and Wheels.
  3. Install and fully seat the wheel nuts in order to securely retain the rotor to the hub and bearing.
  4. Secure the J 8001 to the steering knuckle. Ensure that the J 8001 button contacts the rotor surface about 13 mm (0.500 in) from the outer edge of the brake rotor.
  5. Set the J 8001 to zero.
  6. Use your hands in order to push and pull the rotor edge near the J 8001 . Observe the dial on the J 8001 .

Does the rotor movement measurement exceed the value shown?

0.1270 mm (0.005 in)

Go to Step 2

Go to Step 3

2

Replace the bearing and hub assembly. Refer to Front Wheel Hub, Bearing, and Seal Replacement in Front Suspension.

Is the repair complete?

--

System OK

--

3

  1. Mark the relationship of the rotor to the hub.
  2. Notice: Whenever the brake rotor has been separated from the wheel bearing flange, clean any rust or foreign material from the mating surface of the rotor and flange with the J 42450 hub cleaning kit. Failure to do this may result in increased lateral runout of the rotor and brake pulsation.

  3. Remove the brake rotor. Refer to Front Brake Rotor Replacement in Disc Brakes.
  4. Clean any rust or foreign material from the mating surface of the rotor and the hub using J 42450-A .
  5. Ensure that the J 8001 button contacts the vertical surface of the hub as close as possible to the outer edge.
  6. Set the J 8001 to zero.
  7. Rotate the hub one complete revolution. Inspect the runout indicated on the dial.

Does the runout indicated on the dial exceed the value shown?

0.040 mm (0.0015 in)

Go to Step 2

System OK